I did some numbers in regards to size, RPMs, and average height (of a person), and this is what I have come up with so far, sorry in advance for the short hand. And if anyone has anything to add to it, or sees where I might have gotten something wrong, please let me know. I also used the more common "1.12" instead of the technical "1.118" to shorten it a bit in the calculations.
"Based on RCF equation (Relative centrifugal force)"
G=G-force(RCF) R=Radius RPM=Rotations per minute
Centrifugal force calculation over 1/2 rpm/ 3.57km radius
G=1.12 x R(mm) x (RPM/1000)^2
1=1.12 x R(mm) x (0.5/1000)^2
1=1.12 x R(mm) x (.0005)^2
1=1.12 x R(mm) x .00000025
R(mm)=1/(1.12 x .00000025)
R(mm)=1/.00000028
R(mm)=3,571,428.5714mm
R(km)=3.5714285714km
3.571(km)=2.218(mi) Radius//////7.14km=4.436mi Diameter
average height 5'6" = 1676.4mm
G=1.12x3,569,752.17(mm)x(.00000025)
G=.99953
Difference in G-force felt from head to toe=.000469G at current estimate.
!!!!!Outer ring rotation exceeding 418 mph!!!!!
...over 1 rpm/ .89km radius
1=1.12xRx(.000001)
R=1/0.00000112
R=892,857.14mm
R=0.892857(km)=0.5548(mi)/////1.79(km)=1.1(mi) Diameter
avg height
G=0.00000112x891,180.74
G=.998
Difference in G-force felt (head to toe) = .002G at current estimate
!!!!!Outer ring rotation exceeding 207 mph!!!!!
...over 1.5 rpm/ ~0.40km radius
G=1.12xRx(1.5/1000)^2
1=1.12xRx(.00000225)
1=0.00000252xR
R=396,825.4mm//~0.40km=~0.25mi///////~0.74km=~0.5mi Diameter
avg height
G=1.12x395,149x(.00000225)
G=.99577
DIff. in G (h.t.t.) = ~0.004G at current estimate
!!!!!Outer ring rotation exceeding 141 mph!!!!!
If we are willing to lower the 1G to 3/4G, we could go to a smaller scale at lower RPMs as well.